Tesla's Flying Machine
Tesla's Flying Stove
In Motion - Rotating
"Not the airplane, the flying machine," responded Dr. Tesla.
Allow a moment for the 1.2 megs of images to load.
Watch 2 that are opposite each other, then the other two.
observe that each opposite pair sets up a back and forth motion
on a plane and the 2 oscillations combined describe a circle.
photographed on Fri., March 24th, 2006
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Collectively, the center of orbit of the four "eccentrics" defines
a circle for which the center point is the center of mass for the
frame the eccentrics are built on. That creates the force field.
There is no need to get "hung up" trying to accomplish great precision.
Just make it as accurate as you can, like within a milimeter, and make
adjustments
after you have put it together. Eventually, this will be the centerpiece
of a "flying machine" and this whole framework will be adjustable - to
control the speed and direction of the craft.
The Effect of Gravity
The radius of the earth varies from about 6357 (polar) to 6378 (equatorial) km.
The acceleration of gravity can be found by using a pendulum or, more
precisely, by laser timing of an object falling freely in a vacuum. The
result is about 9.8 m/s^2. It varies with latitude and elevation.
For small amplitude oscillations, the period of the pendulum is
proportional to the square root of the length (radius) and is inversely
proportional to the square root of the acceleration of gravity.
Newton's law of universal gravitation
About fifty years after Kepler announced the laws now named after him,
Isaac Newton showed that every particle in the Universe attracts every
other with a force which is proportional to the products of their masses
and inversely proportional to the square of their separation.
Hence:
If F is the force due to gravity, g the acceleration due to gravity, G the
Universal Gravitational Constant (6.67x10-11
N.m2/kg2), m the mass and r the distance between two
objects. Then
F = G m1 m2 / r2
Acceleration due to gravity outside the Earth
It can be shown that the acceleration due to gravity outside of a spherical
shell of uniform density is the same as it would be if the entire mass of
the shell were to be concentrated at its center.
Using this we can express the acceleration due to gravity (g') at a radius
(r) outside the earth in terms of the Earth's radius (re) and
the acceleration due to gravity at the Earth's surface (g)
g' = (re2 / r2) g
Acceleration due to gravity inside the Earth
Here let r represent the radius of the point inside the earth. The
formula for finding out the acceleration due to gravity at this point
becomes:
g' = ( r / re )g
In both the above formulas, as expected, g' becomes equal to g when
r = re.
a satellite orbiting at an altitude of 22,300 miles would require exactly 24
hours to orbit the Earth
Earth's Equatorial radius = 3963 miles
so the difference in gravity at 22,300 + 3963 (r) miles is
39632 / 26,2632 = 15,705,369 / 689,745,000 = .0227692
= 2.3% of our gravity = 1/44 of our gravity here at the surface
One must get up at least about 4000 mi. just to get to where the gravity is
1/4th of our surface gravity. Or about 9,000 mi above the surface to get
to 1/10th our gravity.
Here is a July 14th 2003 depiction of many of our satelites in orbit.
The ring being those at the 22,300 mi, geostationary, distance.
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