Tesla's Motor - a motors center-line view


Tesla's Flying Machine


Tesla's Flying Stove


In Motion - Rotating

"Not the airplane, the flying machine," responded Dr. Tesla.


Allow a moment for the 1.2 megs of images to load.


Watch 2 that are opposite each other, then the other two.

observe that each opposite pair sets up a back and forth motion
on a plane and the 2 oscillations combined describe a circle.

photographed on Fri., March 24th, 2006




Tesla Space Drive Force Field generator


Collectively, the center of orbit of the four "eccentrics" defines a circle for which the center point is the center of mass for the frame the eccentrics are built on. That creates the force field. There is no need to get "hung up" trying to accomplish great precision. Just make it as accurate as you can, like within a milimeter, and make adjustments after you have put it together. Eventually, this will be the centerpiece of a "flying machine" and this whole framework will be adjustable - to control the speed and direction of the craft.







The Effect of Gravity



The radius of the earth varies from about 6357 (polar) to 6378 (equatorial) km.

The acceleration of gravity can be found by using a pendulum or, more precisely, by laser timing of an object falling freely in a vacuum. The result is about 9.8 m/s^2. It varies with latitude and elevation.

For small amplitude oscillations, the period of the pendulum is proportional to the square root of the length (radius) and is inversely proportional to the square root of the acceleration of gravity.



Newton's law of universal gravitation

About fifty years after Kepler announced the laws now named after him, Isaac Newton showed that every particle in the Universe attracts every other with a force which is proportional to the products of their masses and inversely proportional to the square of their separation.

Hence:

If F is the force due to gravity, g the acceleration due to gravity, G the Universal Gravitational Constant (6.67x10-11 N.m2/kg2), m the mass and r the distance between two objects. Then

F = G m1 m2 / r2

Acceleration due to gravity outside the Earth

It can be shown that the acceleration due to gravity outside of a spherical shell of uniform density is the same as it would be if the entire mass of the shell were to be concentrated at its center.

Using this we can express the acceleration due to gravity (g') at a radius (r) outside the earth in terms of the Earth's radius (re) and the acceleration due to gravity at the Earth's surface (g)

g' = (re2 / r2) g


Acceleration due to gravity inside the Earth
Here let r represent the radius of the point inside the earth. The
formula for finding out the acceleration due to gravity at this point becomes:

g' = ( r / re )g

In both the above formulas, as expected, g' becomes equal to g when r = re.




a satellite orbiting at an altitude of 22,300 miles would require exactly 24 hours to orbit the Earth

Earth's Equatorial radius = 3963 miles


so the difference in gravity at 22,300 + 3963 (r) miles is
39632 / 26,2632 = 15,705,369 / 689,745,000 = .0227692
= 2.3% of our gravity = 1/44 of our gravity here at the surface


One must get up at least about 4000 mi. just to get to where the gravity is 1/4th of our surface gravity. Or about 9,000 mi above the surface to get to 1/10th our gravity.


earth surrounded by its orbiting artificial satelites
Here is a July 14th 2003 depiction of many of our satelites in orbit.
The ring being those at the 22,300 mi, geostationary, distance.